Question:
a+b+c=o find the value of a2\bc+b2/ca+c2/ab
Answer:
We know that a3 + b3 + c3 - 3abc = (a + b + c)(a2 + b2 + c2 - ab - bc - ca)
Given, a + b + c = 0
So, a3 + b3 + c3 - 3abc = 0
=> a3 + b3 + c3 = 3abc
=> a3/abc + b/3abc + c3/abc = 3abc/abc
=> a2/bc + b2/ac + c2/ab = 3
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